Question

example if s=2t^3-3t^2+2 find the position,velocity and acceleration of a particle at the end of 2 second S is measured in metre and T in second ​

Answer 1

s = 2t³-3t²+2

t = 2 sec

s = 2(2)³-3(2)²+2

= 16-12+2

= 6 m

v = s/t

= 6/2

= 3 m/s

a = (v-u)/t

= (3-0)/2

= 3/2

= 1.5 m/s²