EXAMPLE
Prove that
Cháy = 3cos
cosx-48 cos x + 18 cos X - 1. I
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Answers
Answer:
hello buddy ❤️ here is ur answer
Sinx + sin²x + sin³x = 1sin³x + sinx = 1 - sin²xsin³x + sinx = cos²xtake square both sides,(sin³x + sinx)² = cos⁴xsin^6x + sin²x + 2sin⁴x = cos⁴x(1-cos²x)³ + (1 - cos²x) + 2(1-cos²x)² = cos⁴x1 - 3cos²x + 3cos⁴x - cos^6x + 1 - cos²x + 2 + 2cos⁴x - 4cos²x = cos⁴x-cos^6x + 4cos⁴x - 8cos²x + 4 = 0cos^6x - 4cos⁴x + 8cos²x - 4 =0cos^6x - 4cos⁴x + 8cos²x = 4hence, proved
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Step-by-step explanation:
i
Answer:
Sinx + sin²x + sin³x = 1sin³x + sinx = 1 - sin²xsin³x + sinx
= cos²xtake square both sides,(sin³x + sinx)²
= cos⁴xsin^6x + sin²x + 2sin⁴x = cos⁴x(1-cos²x)³ + (1 - cos²x) + 2(1-cos²x)²
= cos⁴x1 - 3cos²x + 3cos⁴x - cos^6x + 1 - cos²x + 2 + 2cos⁴x - 4cos²x = cos⁴x-cos^6x + 4cos⁴x - 8cos²x + 4
= 0cos^6x - 4cos⁴x + 8cos²x - 4
=0cos^6x - 4cos⁴x + 8cos²x = 4