Question

Examples
0.05 M NaOH solution offered a resistance of 31.6 ohm
in a conductivity cell at 298 K. If the area of the plates
of the conductivity cell is 3.8 cmé and distance between
them is 1.4 cm, calculate the molar conductivity of the
sodium hydroxide solution.​

Answer 1

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Explanation:

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Answer 2

Answer:

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Explanation:

The relationship between conductivity κ, resistance R and the cell constant b is

κ=

R

1

×b

κ=

31.6Ω

1

×0.367/cm

κ=0.0116S/cm

The relationship between molar conductivity Λ

m

, conductivity κ and molar concentration C is

Λ

m

=

C

1000κ

Λ

m

=

0.05m

1000×0.0116S/cm

Λ

m

=232.3Scm

2

/mol

Hence, the molar conductivity is 232.3Scm

2

/mol