Question

Examples 111
Solve the following differential equations:
1. p2 + p - 2 = 0;​

Answer 1

हिंदी में खोजें

p2 पी 2 0

How to solve your problem

2

+

−

2

=

0

p^{2}+p-2=0

p2+p−2=0

Quadratic formula

Factor

1

Use the quadratic formula

=

−

±

2

−

4

√

2

p=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

p=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original

Answer 2

first collect like terms.

2p + p - 2 = 0

→ 3p - 2 = 0

then we move the constant to the other side and change it's sign.

→ 3p = 0 + 2

→ 3p =2

Now for the last step , read the explanation properly. Since you can see the question was p2 + p - 2 = 0 , so here the "2p" is in multiplication form and the rule is that when we change the places we Also have to change the sign. hence -

→ p = 2

—

3

mark me brainliest!!!!