Question

examples for divisibility rule of 6and 7​

Answer 1

Answer:

Rule for 6: The prime factors of 6 are 2 and 3. So for a number to be divisible by 6, it must also be divisible by 2 and 3.

for divisibility by 7 is a three steps process:

1.Take the last digit of the number you’re testing and double it.

2.Subtract this number from the rest of the digits in the original number.

3.If this new number is either 0 or if it’s a number that’s divisible by 7, then you know that the original number is also divisible by 7. If you can’t easily tell yet if the new number is divisible by 7, go back to the first step with this new smaller number and try again.

Step-by-step explanation:

ex. for 6: lets take the number 12

prime factors of 12= 2 x 2 x 3

so it is divisible by 6 as it can be divided by 3 and 2

ex. for 7: lets take the number 203

1.The last digit of 203 is 3, so double that is 3 x 2 = 6.

2.Subtracting this new number, 6, from 20 (the remaining digits of the original number 203) gives 14.

3.Since 14 is divisible by 7, we can immediately tell that the original number, 203, must also be divisible by 7.

hope it helps!!!!!!