Math, asked by sanku28598, 2 months ago

Examples
Mr. Desar invested Rs. 5000- on ist of every month for 5 months in a SIP
There was no entry load charged Find the average price , Mr. Desai paid
wsing the Rupee cost Averaging method. After 6 months ,he sold all his
units when NAV was Rs. 51.64 with contingent deferred sales charge
(CDSC) as 2 25%. Find his net gain. (Calculations are correct to 2 digits
decimal
of MF with NAV as 48.15. 52.83.41.28,35.44 & 32.65 respectively answer ​

Answers

Answered by Anonymous
0

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Similar questions