Examples
Mr. Desar invested Rs. 5000- on ist of every month for 5 months in a SIP
There was no entry load charged Find the average price , Mr. Desai paid
wsing the Rupee cost Averaging method. After 6 months ,he sold all his
units when NAV was Rs. 51.64 with contingent deferred sales charge
(CDSC) as 2 25%. Find his net gain. (Calculations are correct to 2 digits
decimal
of MF with NAV as 48.15. 52.83.41.28,35.44 & 32.65 respectively answer
Answers
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Answer:
This implies that
x2+2ax=4x−4a−13
or
x2+2ax−4x+4a+13=0
or
x2+(2a−4)x+(4a+13)=0
Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.
Hence we get that
(2a−4)2=4⋅1⋅(4a+13)
or
4a2−16a+16=16a+52
or
4a2−32a−36=0
or
a2−8a−9=0
or
(a−9)(a+1)=0
So the values of a are −1 and 9.
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