Question

EXAMPLL
Two bodies A and B of equal masses are supplied with equal amount of heat energy. If
rise in temperature of A is more than that in B, what is the relation between their specific
heats?​

Answer 1

Answer:  Specific heat of A is less than that of B.

Explanation: For body A, Q=m×sA×ΔθA

and for body B, Q=m×sB×ΔθB

Dividing (1) by (2), SASB=ΔθAΔθB

This shows that specific heat is inversely proportional to rise in temperature, Thus, specific heat of A is less than that of B.

Answer 2

Explanation:

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