Exanine wheather x+2 is factor x3+2x2+3x+6
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Answered by
1
Step-by-step explanation:
Given p(x)=x
3
+2x
2
+3x+6 and g(x)=x+2
Then g(x)=0 so x=−2 replace x by −2 we get
p(−2)=(−2)
3
+2(−2)
2
+3(−2)+6
p(−2)=−8+8−6+6
p(−2)=0
So remainder is zero then x+2 is factor of x
3
+2x
2
+3x+6
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0
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