exaplain roults law with graph ?
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Raoult's law (/ˈrɑːuːlz/ law) is a law ofthermodynamics established by French chemist François-Marie Raoult in 1887. [1] It states that the partial vapor pressure of each component of an ideal mixture of liquids is equal to the vapour pressure of the pure component multiplied by its mole fraction in the mixture. In other words it is stated as the relative lowering of vapour pressure of a dilute solution containing nonvolatile solute is equal to the mole fraction of solute in the solution.
Mathematically, Raoult's law for a single component in an ideal solution is stated as
{\displaystyle p_{i}=p_{i}^{\star }x_{i}},
where {\displaystyle p_{i}} is the partial pressure of the component {\displaystyle i} in the gaseous mixture (above the solution), {\displaystyle p_{i}^{\star }} is the vapor pressure of the pure component {\displaystyle i}, and {\displaystyle x_{i}} is the mole fractionof the component {\displaystyle i} in the mixture (in the solution).[2]
Once the components in the solution have reached equilibrium, the total vapor pressure of the solution can be determined by combining Raoult's law with Dalton's law of partial pressures to give
{\displaystyle p=p_{\rm {A}}^{\star }x_{\rm {A}}+p_{\rm {B}}^{\star }x_{\rm {B}}+\cdots }.
If a non-volatile solute (zero vapor pressure, does not evaporate) is dissolved into a solvent to form an ideal solution, the vapor pressure of the final solution will be lower than that of the solvent. The decrease in vapor pressure is directly proportional to the mole fraction of solute in an ideal solution.
{\displaystyle p=p_{\rm {A}}^{\star }x_{\rm {A}}}{\displaystyle \Delta p=p_{\rm {A}}^{\star }-p=p_{\rm {A}}^{\star }(1-x_{\rm {A}})=p_{\rm {A}}^{\star }x_{\rm {B}}}
Mathematically, Raoult's law for a single component in an ideal solution is stated as
{\displaystyle p_{i}=p_{i}^{\star }x_{i}},
where {\displaystyle p_{i}} is the partial pressure of the component {\displaystyle i} in the gaseous mixture (above the solution), {\displaystyle p_{i}^{\star }} is the vapor pressure of the pure component {\displaystyle i}, and {\displaystyle x_{i}} is the mole fractionof the component {\displaystyle i} in the mixture (in the solution).[2]
Once the components in the solution have reached equilibrium, the total vapor pressure of the solution can be determined by combining Raoult's law with Dalton's law of partial pressures to give
{\displaystyle p=p_{\rm {A}}^{\star }x_{\rm {A}}+p_{\rm {B}}^{\star }x_{\rm {B}}+\cdots }.
If a non-volatile solute (zero vapor pressure, does not evaporate) is dissolved into a solvent to form an ideal solution, the vapor pressure of the final solution will be lower than that of the solvent. The decrease in vapor pressure is directly proportional to the mole fraction of solute in an ideal solution.
{\displaystyle p=p_{\rm {A}}^{\star }x_{\rm {A}}}{\displaystyle \Delta p=p_{\rm {A}}^{\star }-p=p_{\rm {A}}^{\star }(1-x_{\rm {A}})=p_{\rm {A}}^{\star }x_{\rm {B}}}
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According to Raoult's Law,
you will double its partial vapour pressure. ... In other words, the
partial vapour pressure of A at a particular temperature is proportional
to its mole fraction. If you plot a graph of the partial vapour pressure of A against its mole fraction, you will get a straight line.
ranjitha120143:
its ok frnd
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