Exaplaintion S=ut+1/2a[t]2 formula
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What is s=ut+1/2at^2?
This is the third equation of the three uniformly accelerated motion.
Here,
s is the distance
u is the initial velocity
a is the acceleration
t is the time
Let me derive this equation for you graphically.
In this graph,
v is the final velocity of the body and other variables have their usual significance.
We know,
Acceleration (a)= (v-u)/t
=>v-u=at…(eq.1)
Now,
Distance travelled in time t = Area of trapezium OABD
=Area of rectangle OAED+ Area of triangle ABE
=>S=OA*OD +1/2 BE*AE
=u*t+1/2*(v-u)*t
But from equation 1
v-u=at
=u*t+1/2*(at)*t
Therefore,
S=ut+1/2at^2
Hope this helps you.What is s=ut+1/2at^2?
This is the third equation of the three uniformly accelerated motion.
Here,
s is the distance
u is the initial velocity
a is the acceleration
t is the time
Let me derive this equation for you graphically.
In this graph,
v is the final velocity of the body and other variables have their usual significance.
We know,
Acceleration (a)= (v-u)/t
=>v-u=at…(eq.1)
Now,
Distance travelled in time t = Area of trapezium OABD
=Area of rectangle OAED+ Area of triangle ABE
=>S=OA*OD +1/2 BE*AE
=u*t+1/2*(v-u)*t
But from equation 1
v-u=at
=u*t+1/2*(at)*t
Therefore,
S=ut+1/2at^2
Hope this helps you.☺️
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