Question

excellent maths q pls someone pls solve

Answer 1

here is your soln.
product of root=c/a=3/3=1
so let one root be k then other is k²
k*k²=k³=1
k=1 k²=1
sum of roots=-p /a
2=-p/3
p=-6

Answer 2

Let a, a^2 be the roots of the Equation 3x^2 + px + 3 = 0.

Now,

= > Sum of roots = -p/3

a + a^2 = -p/3  


= > Product of roots = 3/3

a * a^2 = 1

a^3 = 1  

a^3 - 1 = 0

(a - 1)(a^2 + a + 1) = 0

Given that p > 0.

a^2 + a + 1 = 0

(-p/3) + 1 = 0

-p + 3 = 0

= > p = 3.



Therefore the value is p = 3.



Hope this helps!