Chemistry, asked by shreyaa14, 23 days ago

exceptions in modern periodic table??​

Answers

Answered by Anonymous
6

Question:

What are all exceptions in modern periodic table?

Answer:-

{\color{purple}{†\:}{\sf{\color{gold}{Variation \:in\: ionisation \:enthalpies:}}}}

Ionisation enthalpy increases with increases in atomic number along the period. Some elements show irregularities in this trend due to type of electron to be removed and the extra stability of the exactly half-filled and completely filled electronic configurations.

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{\color{purple}{†}{\sf{\color{gold}{Variation \:along\: the\: period:}}}}

In the second period Li to Be, the ionisation enthalpy increases due to increased nuclear charge and smaller atomic radius of Be as compared that of Li.

For Be to B, although the nuclear charge of B is more than that of be, yet the ionisation enthalpy of B is lower than that of Be.

For B to C to N, the first ionisation enthalpy of these elements keeps on increasing due to progressively increasing nuclear charge and decreasing atomic radius.

For N to O, the first ionisation enthalpy of oxygen is lower than that of Nitrogen although the nuclear charge of O is higher than that of N.

For O to F to Ne, the first ionisation enthalpy increases from O to F to Ne because of the increasing nuclear charge.

Note:- ★[Similar variations in the first ionisation enthalpies of the elements of the third period have been observed.]★

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{\color{purple}{†}{\sf{\color{gold}{Variation \:of\: electron\:gain \:enthalpy}}}}

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In general, the electron gain enthalpies become less negative as we move down a group. But the electron gain enthalpies of some of the elements of second period that is O, and F are however, less negative than the corresponding elements that is s and Cl of the third period.

Thus, the electron gain enthalpy of F is unexpectedly less negative than that of Cl.

Also, the electron gain enthalpy of noble gases is positive as atoms of these elements have completely filled subshells.

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{\color{purple}{†}{\sf{\color{gold}{Variation \:in\: atomic \:radii:}}}}

The atomic radius abruptly increases as we move from halogen (F) to the inert gas (Ne). This is due to the reason that in case of inert gases all the orbitals are completely filled and hence the electronic repulsions are maximum.

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{\color{purple}{†}{\sf{\color{gold}{Variation \:of\: valence\:in\:a \: period:}}}}

As we move across a period from left to right, the number of valence electrons increases from left to right, the number of valence electrons increases from 1 to 8. But the valence of elements with respect to H or O first increases from 1 to 4 and then decreases to zero.

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{\color{purple}{†}{\sf{\color{gold}{Electronegativity:}}}}

This is the easiest of the exceptions. We have said that electronegativity increases to the right. This is true except that the trend does NOT include the noble gases. That means that fluorine has the highest electronegativity, not Ne or He. This is because the definition of electronegativity contains the phrases "in a covalent bond." Since the noble gases don't bond, they don't have electronegativities.

It should be noted that a few of the noble gases have been forced to bond (at high temperture and high pressure with fluorine). You may find tables that, therefore, list values for the electronegativity of Xe and Kr, but these are not terribly important values to know.

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Answered by llBrutalEmpirell
6

Explanation:

Question:

\fbox\red{What are all exceptions in modern periodic table?}

Answer:-

{\color{purple}{†\:}{\sf{\color{gold}{Variation \:in\: ionisation \:enthalpies:}}}}†

Ionisation enthalpy increases with increases in atomic number along the period. Some elements show irregularities in this trend due to type of electron to be removed and the extra stability of the exactly half-filled and completely filled electronic configurations.

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