Chemistry, asked by Aryann9797, 10 months ago

Excess of na2s2o3 solution reacts with aqueous cuso4 to give

Answers

Answered by kusum2003kin
11
Naso4+ cu2s2o3

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Answered by qwcasillas
1

Excess sodium thiosulphate reacts with copper sulphate to form a complex compound Sodium cuprothiosulphate.

  • Sodium thiosulphate is a reducing agent.
  • It reduces copper sulphate to cupric thiosulphate in the first step.
  • One more mole of sodium thiosulphate reduces cupric thiosulphate to yield a cuprous compound which on further reduction forms a complex, Sodium cuprothiosulphate.
  • The reactions are depicted below:

                 Na_{2}S_{2} O_{3}  + CuSO_{4} →  CuS_{2}O_{3} + Na_{2} SO_{4}

                 2CuS_{2}O_{3} + Na_{2} S_{2} O_{3}Cu_{2} S_{2}O_{3} + Na_{2} S_{4} O_{6}

                 3Cu_{2} S_{2}O_{3} +2 Na_{2} S_{2} O_{3}Na_{4} [Cu_{6} (S_{2} O_{3})_{5} ]

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