Question

excess pressure of one soap bubble is four times more than the other . the ratio of volume of first bubble to anothwr one is

Answer 1

the ratio will be 4:1

Answer 2

∆P1/∆P2=r2/r1

=4

=r2=4r1

V1/V2=(4/3πr1^3)/(4/3πr2^3)

= (1/4)^3

=1/64