Exclusive or duality is equal to its complement. Explain
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XOR, A ⊕ B = A′B+AB′
Dual of XOR = (A′+B).(A+B′) = A'A+A'B'+AB+BB' = AB+A'B'= XNOR
thus, dual of XOR is same as its complement.
Dual of XOR = (A′+B).(A+B′) = A'A+A'B'+AB+BB' = AB+A'B'= XNOR
thus, dual of XOR is same as its complement.
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