Question

EXE
1. The units digit of a two-digit number is 3 and seven times the sum of the digits is the
number itself. Find the number.
​

Answer 1

Given:

The unit of a two-digit number is 3

To find:

So,

Let the number be x

The unit digit is 3

Also, let tens digit number be 10x

Now

The number be (10x + 3)

According to the question

Seven times the sum of the digits is the number itself

⇒ 7(x + 3) = 10x + 3

⇒ 7x + 21 = 10x + 3

⇒ 21 - 3 = 10x - 7x

⇒ 18 = 3x

⇒ 18 ÷ 3 = x

∴ 6 = x

Therefore,

The ten digit number is 6

So the number is

= 10x + 3

= 10*6 + 3

60 + 3 = 63

Hence,

The number is 63

Answer 2

Answer:

The Number is 63.

Step-by-step explanation:

• Unit of two digit number is 3

• Let the tens digit number be x

• The Number will be 10x + 3

• Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

• The required number = 10x + 3 = 10(6) + 3 = 63.