Question

EXERCI
1. Solve the following pair of linear equations by the elimination and substitution
method:
x+y=5 and 2x-3y=4​

Answer 1

Answer:

Using substitution method,

x+y=5

x= 5-y. (1)

2x-3y= 4

10-2y=4

10-2y =4

y=6/2=3

x= 2

Using elimination method,

x+y= 5. (1)

2x -3y=4

Multiplying (1) with 2,

2x+2y=10

2x-3y=5

5y = 15

y = 3.

y = 3.x= 2

Answer 2

Step-by-step explanation:

Elimination method :

-->throughout multiplying 2

2x+2y=10

2x-3y=4

------------------

5y=6

y= 6/5

putting y=6/5 in x+y=5

x+6/5=5

x=5-6/5

x= -3.8

Substitution method :

x+y=5-----(1)

2x-3y=4------(2)

putting x=5-y in (2)

2(5-y)-3y=4

10-2y-3y=4

10-5y=4

-5y=4-10

-5y=-6

y= 6/5

putting y=6/5 in (1)

x+6/5=5

x=5-6/5

x= -3.8

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