Question

EXERCISE - 1.1
1.
Use Euclid's division alge
(i) 900 and 270
2.
Use Euclid division lemn
nr 6​

Answer 1

Answer:

Euclid's division lemma :

Let a and b be any two positive

integers .Then there exists two

unique whole numbers q and r

such that

a = bq + r ,

0 ≤ r < b

Now ,

900 and 270 , start with the larger

integer , that is 900. Apply the

Division lemma , we get

900 = 270 × 3 + 90

270 = 90 × 3 + 0

The remainder has now become

zero . Now our procedure stops.

Since the divisor at this stage is 90.

Therefore ,

HCF ( 900 , 270 ) = 90