EXERCISE - 1.2
1. Express each of the following numbers as a product of its prime factors.
iv) 5005
(v) 7429
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Step-by-step explanation:
*Since, the prime factors of 5005 are 5, 7, 11, 13. Therefore, the product of prime factors = 5 × 7 × 11 × 13 = 5005.
* Thus, 7429 is expressed as 17 × 19 × 23 as a product of its prime factors.
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(i) 140
140=2×70
=2×2×35
=2×2×5×7
=2×2×5×7×1
(ii) 156
156=2×78
=2×2×39
=2×2×3×13
=2×2×3×13×1
(iii) 3825
3825=3×1275
=3×3×425
=3×3×5×85
=3×3×5×5×17
=3×3×5×5×17×1
(iv) 5005
5005=5×1001
=5×7×143
=5×7×11×13
=5×7×11×13×1
(v) 7429
7429=17×437
=17×19×23
=17×19×23×1(i) 140
140=2×70
=2×2×35
=2×2×5×7
=2×2×5×7×1
(ii) 156
156=2×78
=2×2×39
=2×2×3×13
=2×2×3×13×1
(iii) 3825
3825=3×1275
=3×3×425
=3×3×5×85
=3×3×5×5×17
=3×3×5×5×17×1
(iv) 5005
5005=5×1001
=5×7×143
=5×7×11×13
=5×7×11×13×1
(v) 7429
7429=17×437
=17×19×23
=17×19×23×1
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