Math, asked by kattimanijyoti98, 8 months ago

EXERCISE 1.2
1. If 21y5 is a multiple of 9, where y is a digit, what is the value of y?​

Answers

Answered by evanbinson
2

Number 21y5

Multiple of 9

Value of digit y = 2+1+y+5 = 8+y

Closest multiple of 9 = 18

8+y=18

   y=18-8=10

  y=10 i.e 1 ten

no: 2115.

2+1+1+5=9

This is the answer.

Hope you have a great day! :)

Answered by navyabangia25011998
0

Answer:

8 is the value of y

property is a number is divisible by 9 if sum of all digits is divisible by 9

2+1+y+5=9

where y =8

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