exercise 1.5 2nd sum.....
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In the attachment..
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↪ Equation :
x-y = 5 ------(1)
3x + 2y = 25 -----(2)
▶Method of Solution ▶
Solving By Elimination Method ↙
x-y = 5
3x + 2y = 25
Step : Multiply Equation (1) by 3
↪ Multiply Equation (2) by 1
↪x-y = 5 × (3)
3x + 2y = 25 × (1)
--------------------------
▶ 3x-3y = 15
▶ 3x+2y = 25
----------------------
-5y = - 10
•°• y = 2
↪Substitute the Value of Y in the Equation (1)
↪ x - y = 5
↪ x -2 = 5
↪ x = 5+2
↪ x = 7
Hence, Value of x and y are 7 and 2 Respectively!
Regards (Moderator!)
x-y = 5 ------(1)
3x + 2y = 25 -----(2)
▶Method of Solution ▶
Solving By Elimination Method ↙
x-y = 5
3x + 2y = 25
Step : Multiply Equation (1) by 3
↪ Multiply Equation (2) by 1
↪x-y = 5 × (3)
3x + 2y = 25 × (1)
--------------------------
▶ 3x-3y = 15
▶ 3x+2y = 25
----------------------
-5y = - 10
•°• y = 2
↪Substitute the Value of Y in the Equation (1)
↪ x - y = 5
↪ x -2 = 5
↪ x = 5+2
↪ x = 7
Hence, Value of x and y are 7 and 2 Respectively!
Regards (Moderator!)
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