Math, asked by malakarjaydev7, 1 month ago

EXERCISE 1 (E)
1. The product of two rational numbers is -12. If one of the number is -8, find the other,

Answers

Answered by sahaprottus
1

Answer:

3/2

Step-by-step explanation:

another number= -12/-8 = 3/2

Answered by Anonymous
47

\large\sf\underline{Given\::}

  • Product of two numbers is -12

  • One of the number is -8

\large\sf\underline{To\:find\::}

  • The number whose product with -8 gives us -12.

\large\sf\underline{Concept\::}

Here in the question we are said that the product of two numbers is -12 . One of the number is given as -8 . We are asked to find the other number. In order to do so we would assume the other number to be x and then frame an equation following the question. Solving the equation we would get the other number whose product with -8 gives -12 .

\large\sf\underline{Assumption\::}

Let the other number be x.

\large\sf\underline{Solution\::}

Let frame up an equation :

\bf\:Assumed\:number\: \times (-8) =(-12)

\sf\implies\:x \times (-8) =(-12)

\sf\implies\:-8x =-12

  • Now transposing -8 to RHS it goes to the denominator

\sf\implies\:x =\frac{-12}{-8}

  • Signs gets cancelled out

\sf\implies\:x =\frac{\cancel{-}12}{\cancel{-}8}

\sf\implies\:x =\frac{12}{8}

  • Reducing the fraction to the lower terms

\sf\implies\:x =\cancel{\frac{12}{8}}

\sf\implies\:x =\cancel{\frac{6}{4}}

\small{\underline{\boxed{\mathrm\red{{\mathfrak{\implies\:x\:=\:\frac{3}{2}}}}}}}

\large\sf\underline{Verifying\::}

Let's check if we got the correct number. How would we check!? We just need to substitute the value of x as 3 / 2 in the equation we had framed. Doing so and solving it , if we get LHS = RHS, our answer would be correct.

Our equation : \sf\:x \times (-8) =(-12)

  • Substituting the value of x

\sf\rightarrow\:\frac{3}{2} \times (-8) =(-12)

\sf\rightarrow\:\frac{3}{2} \times -8=-12

  • Multiplying the numbers

\sf\rightarrow\:\frac{-24}{2} =-12

  • Reducing the fraction to the lower terms

\sf\rightarrow\:\cancel{\frac{-24}{2}} =-12

\sf\rightarrow\:-12 =-12

\bf\rightarrow\:LHS=RHS

\bf\color{gray}{Hence\:verified} {\checkmark}

__________________________

\dag\:\underline{\sf So\:the\:required\:number\:is\:\frac{3}{2}}

!! Hope it helps !!

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