Math, asked by chavadamkomala, 7 months ago

Exercise
1)
Find the least number which when divided by 12, 16, 18, 21 and 28 leaves the same
remainder 7 in each case.
2)
Find the least number which when diminished by 8, is divisible by each of the numbers
12, 15, 20 and 54.
[Hint: Required number = (L.C.M of 12, 15, 20, 54) + 8]
Find the smallest number which when increased by 5 is divisible by each of the
3)
numbers 48, 60, 72 and 108.
[Hint: Required number = (L.C.M of 48, 60, 72, 108) - 5]
4)
Find the greatest number of four digits which exactly divisible by each one of the
numbers 12, 18, 21 and 28.​

Answers

Answered by behanipooja
5

Step-by-step explanation:

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: [A]. = 548.

Answered by jhumasaw01
3

Answer:

28 Ans.

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