Math, asked by 10A33, 9 months ago

Exercise
1. Find the sum of the following series
(i) 1 + 2 + 3 + +60 (ii) 3 + 6+
(iv) 1+4 +9+16 + ... +225 (v)
648...21
(vi) 10 +11° +12 + ... +20° (vii) 1+3+5+ ... + 71
If 1+2+3+...+k=325, then find 1+2+3+...+
3. ° +
If 1 +2 +3 + ... +2=44100 then find 1+2+3+...+k.
How many terms of the series 1° +2° +3+... should be taken to get the sum 144002
The sum of the squares of the first n natural numbers is 285, while the sum of their
cubes is 2025. Find the value of n.
:) Rekha has 15 square colour papers of sizes 10 cm, 11 cm, 12 cm..... 24 cm. How mud
area can be decorated with these colour papers?
Find the sum of the series (2-1)+(4"-3") +on++ ...to
(i) n terms (ii) 8 terms
3 (63_53)
10th Standard Mathematid
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Answers

Answered by malhikuldeep17
1

Answer:

part 1

ans 1=1+2+3++60

= 1+2+3+(+60)

= 1+2+3+60

= 3+3+60

= 6+60

=66 ans

ans 2=3+6+

9 ans

where is 3 question

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