Exercise-
1. For the given pairs of numbers, show that the product of their HCF and LCM equals their product:
(i) 27 and 90
(ii) 14 and 21
2. The LCM and HCF of two numbers is 2175 and 145 respectively. If one of the number is 725, find
Answers
Answer:the product of their HCF and LCM equals their product
Step-by-step explanation:
(i) 27 and 90
Hcf of the two numbers = 9
Lcm of these two numbers= 270
product of the numbers = 27 x 90 = 2430
product of the lcm and hcf = 270 x 9 = 2430
➤product of their HCF and LCM equals their product
(ii) 14 and 21
Hcf of the numbers = 7
Lcm of the numbers = 42
Product of the numbers = 21 x 14 = 294
product of Lcm and Hcf = 7 x 42 = 294
➤product of their HCF and LCM equals their product
2.
Lcm of the numbers = 2175
hcf of the numbers = 145
One number = 725
Other number = x
∵product of their HCF and LCM equals their product
725*x = 2175 x 145
725x = 315375
x = 315375/725
x = 435
Note - I did not use calcultor, answers calculated by me only
Hope this helps!!!
Answer:
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