Question

EXERCISE
1. In a AABC, if ZA = 72º and ZB = 63°, find ZC.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given: A ️ ABC where ZA=72°and ZB=63°

i.e.,A=72°/Z ; B=63°/Z

let Z=1 then,

ZA=A=72°, ZB=B=63°, ZC=C

By, angle sum property of a triangle,

A+B+C=180°

72°/Z+ 63°/Z+C=180°

Therefore, C= 180°-135°/Z

This implies, C=180°Z-135°Z÷Z

This implies, C=45°Z/Z

Hence, ZC= 45° (Since, Z=1)