Math, asked by vibhagauniyalishtwal, 6 months ago


EXERCISE 10A
1. Find the simple interest for the following.
a. P = 34000 for 2 years at 8% p.a.
b. P=310,500 for 146 days at 8.75% pa
c. P=19,200 for 11 months at 6.5% p.a,
d. P = 1000 for 5 years at 4% p.a.
e. P = 22,500 for 2.75 years at 8.12% p.a.
f. P = 5000 for 5 years at 5% p.a.

Answers

Answered by aditya2724
0

Answer:

a) 5440

d) 200

f) 1250

explanation

by formula ::

simple interest = principal × rate× time

100

Answered by AnIntrovert
3

Solution

Principal → 34000 ,

Rate → 8 % per annum

Time → 2 Years

SI ⇒ PRT / 100

⇒ 34000 × 8 × 2 / 100

⇒ 5440 rs

Principal → 310500 ,

Rate → 8.75 % per annum

Time → 146 days or 146 / 365 Year

SI ⇒ PRT / 100

⇒ 310500 × 8.75 × 146 / 100 × 365

⇒ 10867.5 rs

Principal → 19200 ,

Rate → 6.5 % per annum

Time → 11 months or 11 / 12 Year

SI ⇒ PRT / 100

⇒ 19200 × 6.5 × 11 / 100 × 12

⇒ 1144 rs

Principal → 1000 ,

Rate → 4 % per annum

Time → 5 Year

SI ⇒ PRT / 100

⇒ 1000 × 4 × 5 / 100

⇒ 200 rs

Principal → 22500 ,

Rate → 8.12 % per annum

Time → 2.75 Year

SI ⇒ PRT / 100

⇒ 22500 × 8.12 × 2.75 / 100

⇒ 5024.25 rs

Principal → 5000 ,

Rate → 5 % per annum

Time → 5 Year

SI ⇒ PRT / 100

⇒ 5000 × 5 × 5 / 100

⇒ 1250 rs

⠀⠀

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