Math, asked by raja3339, 1 month ago

EXERCISE 11.3 1. Evaluate cosec 31º - sec 590 ( iii tan 36 cor 540 cos 12º - sin789 (10) (iv) sin 13° sec 75° ( ) tan 26° tan64º 2. Show that 3. 4. (0) tan 48°tan 16°tan 42° tan 74°= 1 cos36° cos 54°- sin36ºsin 54°= 0. Iftan 2A=cot(A-18), where 2A is an acute angle. Find the value ofA. IftanA=cot B where A and B are acute angles, prove that A+B=90°. IfA, B and Care interior angles of a triangle ABC, then show that A+B =cot 2 2 5. tan 6. Express sin 75°+cos 65° in terms of trigonometric ratios of angles between​

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Answered by joysmery734
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