Question

exercise 11 question number 6(I)​

Answer 1

Answer:

Step-by-step explanation:

In triangle BCD

BC=8cm

DC=17 cm

So by using pythegorams theorem

H^2=b^2+a^2

That is

DC= BC +DB

17square=8square+DB

289=64+DB^2

DB^2=289-64

DB^2=225

So. DB=15

Now using herons formula

√s(s-a)(s-b)(s-c)

S is semi perimeter

So by substituting the values we get and 60 cm square

Now similarly in triangle ABC

By pythegorams theorem we get BA= 12cm

So we can find area by herons formula

That is 54 cm square

By adding both triangles area we get 114cm^2

THANK YOU