Question

EXERCISE 12.2 A park in the shape of a quadrilateral ABCD, has 2 C 90AB = 9m. BC-12 m. CD = 5 m and AD - 8m. How much area does it occupy ​

Answer 1

In triangle BCD using Pythagoras theorem

BD2 = BC2 + CD2

= (12)2 + (5)2

= 144 + 25

BD2 = 169

BD = 13 m

Find area of triangle BCD we get 30 m2

Find area of triangle ABD using Heron's formula we get 35.496 m2

Area of park = Area of triangle ABD + area of triangle BCD = 65.5 m2 approximately.