Math, asked by dganga207, 4 months ago

EXERCISE 13.3
1. The length of a diagonal of a quadrilateral is 28 cm. The lengths of perpendiculars on it from the opposite
vertices are 9 cm and 13 cm. Find the area of the quadrilateral.

Answers

Answered by ashiyanakhan44
2

Answer:

Area of quadrilateral is 308 cm2.

Step-by-step explanation:

Given:

Here the length of a diagonal of a quadrilateral = 28 cm

The length of a perpendicular on it from opposite vertices are 9 cm and 13 cm respectively.

Now,

Area of quadrilateral = \frac{1}{2}\times

2

1

× one diagonal \times× sum of the lengths of the perpendicular drawn from it on the remaining two vertices

= \frac{1}{2}\times 28 \times (9+13)

2

1

×28×(9+13)

= \frac{1}{2}\times 28 \times 22

2

1

×28×22

= 28 \times 1128×11

= 308 cm^2cm

2

Hence area of quadrilateral is 308 cm^2cm

2

.

Answered by vk5466470
1

Answer:

294

Step-by-step explanation:

length of diagonal=28cm

length of quadrilateral=1/2*28*(9+3)

=14*21

=294

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