Question

Exercise-14.1 first one

Answer 1

for this question u need to find their surface areas
SA of cuboid=2(lb+bh+hl)
SA of Cube =6l^2
put the value and then compare the surface areas

Answer 2

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❄❄HERE IS YOUR ANSWER❄❄

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➡Total Surface Area of Cuboid = 2(lb+bh+hl)

[Length of cuboid (l) = 60cm,
Breadth of Cuboid (b) = 40 cm,
Height of cuboid (h) = 50 cm]

So ,

➡2(lb+bh+hl)

➡2(60×40 + 40×50 + 50× 60)

➡2(2400+2000+3000)

➡2(7400)

➡14800 cm²

............

Now , Total Surface Area of Cube = 6a²

[Side of cube = 50cm ]

So,

➡6a²

➡6(50)²

➡6(2500)

➡15000 cm²

Hence, The total surface area of Cuboid is less than Cube , So, Cuboid requires the less amount of material to make.

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