Question

Exercise 14.2
1 Factorise the following
ex

(v) 4x2 - 8x +4​

Answer 1

$\huge{\underline{\mathfrak{\red{Answer:-}}}}$

$\sf{4x^2 - 8x + 4}$

$\sf{4x^2 - 4x - 4x +4}$

$\sf{4x(x-1) -4(x-1)}$

$\sf{(x-1)(4x-4)}$

$\sf{x=1}$

$\sf{x=4/4\:=>x = 1}$

Answer 2

$\color{green}{•••Answer•••}$

${4x}^{2} - 8x + 4 \\ = 4( {x}^{2} - 2x + 1) \\ = 4( {x}^{2} - 2 \times x \times 1 + {1}^{2} ) \\ = 4 {(x - 1)}^{2} \\ = 4(x - 1)(x - 1)$

$\color{green}{•••hope \: it \: helps \: you•••}$