Question

EXERCISE 16.2
1. I21y5 is a multiple of 9, where y is a digit what is the value of y?
2. If 3125 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?

3. If 24x is a multiple of 3, where x is a digit, what is the value of x? (Since 24x is a multiple of 3, its sum of digits 6+x is a multiple of 3: so 6-ris one of these numbers: 0,3,6,9,12, 15, 18. .... But since x is a digit it can only be the 6+x=6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of four different values.)

4. If 3125 is a multiple of 3, where z is a digit, what might be the values of z?​

Answer 1

Answer:

42000000

Step-by-step explanation:

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