Question

EXERCISE 16.2
• If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
If 3175 is a multinle of where is a dinit what is the value of 7?​

Answer 1

Answer:

Since the number 21y5 is a multiple of 9.

So, the sum of its digits 2+1+y+5=8+y is a multiple of 9.

∴(8+y) is either 0 or 9 or 18 or ...

Since y is a digit, so (8+y) must be equal to 9.

i.e., 8+y=9

Step-by-step explanation:

⇒y=9−8=1