Question

EXERCISE 18A
1. Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance
between them is 15 cm​

Answer 1

$\bf \: Given \: :$ ↴

$\sf \: The \: parallel \: sides \: of \: trapezium \: are \: 24 \: cm \: and \: 20 \: cm.$

$\sf \: The \: distance \: between \: them \: is \: 15 \: cm.$

$\bf \: To \: find \: :$ ↴

$\sf \: We \: have \: to \: find \: the \: area \: of \: trapezium.$

$\star \bf \: So, \: Let's \: Start \: \star$

$\sf \: \underline{Area \: of \: trapezium }\: :$ ↴

$\boxed{ \purple{\sf \: \dfrac{1}{2} \: \times \: Sum \: of \: parallel \: sides \: \times Distance \: between \: them.}}$

$\sf \: Putting \: the \: value \: :$ ↴

$\sf \longrightarrow \: \dfrac{1}{2} \: \times (24 + 20) \: \times \: 15 \:$

$\sf \longrightarrow \: \dfrac{1}{2} \: \times 44 \: \times \: 15 \:$

$\sf \longrightarrow \: \dfrac{1}{2} \: \times 660$

$\sf \longrightarrow \: \dfrac{1}{1} \: \times 330$

$\green{ \sf \longrightarrow 330 \: cm ^{2} }$

$\blue{ \red{\star}\: \underline{ \sf \: So, \: Area \: of \: a \: trapezium \: is \: 330 \: cm ^{2} }}$

$\sf More \:to\: know\: about\: trapezium$

(1) Perimeter of trapezium = Sum of all the sides

(2) A trapezium has 4 unequal sides.

(3) Two sides are parallel and two are non-parallel.

(4) Diagonals always bisect each other.

(5) Sum of all interior angles of trapezium is always 360° since it's a quadrilateral .

Answer 2

Given :

• Parrallel Sides of trapezium are 24 cm and 20 cm and the distance between them is 15 cm

To find :

• Area of Trapezium

Solution :

• We know that area of Trapezium is 1/2 Sum of || sides × Distance between them.

✰ Parrallel sides = 24cm ,20cm

✰ Distance between them = 15cm

Area = 1/2 Sum of || sides × Distance

➤ 1/2 (24 + 20) × 15

➤ 1/2 × 44 × 15

➤ 22 × 15 3

➤ 330cm²

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More to know :

• Area of Square = (Side)²

• Area of Rectangle = L × B

• Area of Rhombus 1/2 × D₁ × D₂

• Area of Traingle = 1/2 × B × H

• Area of circle = πr²

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