Question

EXERCISE 2.2
8
1. Find the zeroes of the following quadratig polynomials and verify the relationship between
the zeroes and the coefficients.
4u²+8u
​

Answer 1

Answer:

Step-by-step explanation:

Hey friend !

p(x) = 4u²+8u

4u ( u + 2 ) = 0

[4u + 0 ] [ u + 2 ] ------> factorized form

hence ,

u = 0

u = -2

Here ,

a = 4

b = 8

c = 0

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2

= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0

= c/a = 0/4 = 0

pls mark as brainliest

Answer 2

Answer:

take 4u (u+4)

to find zeros

4u=0,

u+2=0

u=0/4 , u= - 2

u=0 , u= -2

alpha = 0 and beta = -2

relationship

alpha+ beeta =0+(-2)

= -2 = -b/a

= -8/4

= -2

alpha× beta =0×-2=0 = c/a

= 0

HOPE IT HELPS!!!