Question

EXERCISE 2.2
in the zeroes of the following quadratic polynomials and verify the relationship between
the zeroes and the coefficients
(vi) 3x² - x - 4
​

Answer 1

Answer:

BY SPLITTING THE MIDDLE TERM;

- 3x²-4x+3x-4 = 0.

- x(3x-4)+1(3x-4)=0

- (3x-4)(x+1)=0

x=4/3;x=-1

To verify:

sum of zeros=-b/a

4/3+(-1)=-(-1)/3

4-3/3=1/3

1/3=2/3

product of zeros=c/a

4/3×-1=-4/3

-4/3=-4/3

hence proved.

Answer 2

Step-by-step explanation:

there fore sum of zeroes is 1/3=1/3 and the product of zeroes is -4/3 = -4/3