Question

Exercise 2.2 the base of an isosceles triangle is 4/3 cm. the perimeter of the triangle is 62/15 cm. what is the length of either sides of the remaining equal sides?

Answer 1

Base=4/3cm
Let the equal sides be x.
Perimeter=S1+S2+S3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)/15=2x
42/15/2=x
42/15×1/2=x
21/15=x
7/5=x

Thus,
Two equal sides = x = 7/5cm

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Answer 2

Concept

An isosceles triangle is a triangle with two sides of equal length in geometry. It is sometimes stated as having exactly two equal-length sides, and other times as having at least two equal-length sides.

Given

An isosceles triangle has a 4/3 cm base and a 62/15 cm perimeter.

To find

The length of either side of the remaining equal sides.

Solution

By the property of isosceles triangle

Let x be the length of the two equal sides of the triangle.

then,

Perimeter = x+x+4/3

62/15 = 2x+4/3

2x = (62-20)/15

2x = 42/15

x = 21/15

x = 7/5

As a result, the remaining two sides are each 7/5 cm long.