Question

Exercise :- 2.3


1.) Write down the index and radicand for each of the following expressions

$i) \: \sqrt{ \frac{11}{y}}\\\\ii) \sqrt[3] \frac{13}{3x} \\\\iii) \sqrt[5]{ {ab}^{2} }$
Transform the following radical forms into exponential forms. Donot simplify.

$(i) \sqrt{36} \: \: \: \: \: \: \: (ii) \sqrt{1000} \: \: \: \: (iii)\sqrt[3]{8} \: \: \: \: \\ ( iv) \sqrt[n]{q} \: \: \: \: \ (v)\sqrt{(5 - 6 {a}^{2} } ){3} \ \\ \\ (vi) \sqrt[3]{ - 64}$
❎❎❌✖️Spammers account will be reported ❎❎❌✖️

❎❌✖️Don't answer if u don't know how to solve it✖️❌❎

✔️✅✔️✅Correct answer will be brainlest and users all answers will be thanked ✅✔️✅✔️

✔️✅I KNOW A MODERATER PERSONALLY ✔️✅

✖️❎❌DON'T COPY FROM✖️❌❎ GOO.GLE
​

Answer 1

Answer:

2(i) 36½

(ii)(1000)½

(iii) (8)^3/2

(iv)(q)^n/2

(v)(5-6a²)^3/2

(vi)(-64)^3/2

Answer 2

Answer: AHHHHHHHHHH

Area of rhombus = 24 cm²

Length of the other diagonal = 6 cm.

Step-by-step explanation:

Hi,

Given the side of the rhombus, b = 6 cm

Also, Given the altitude of rhombus , h = 4 cm,

Area of the rhombus when base(side) and altitude(h)

are given is given by A = base * height

Thus, Area of rhombus = 6 * 4  cm²

Area of rhombus = 24 cm².

Given one of the diagonal is of length  8 cm,

Let d₁ = 8 cm.

Let the length of the other diagonal be d₂.

If d₁, d₂ length of the diagonals are known, then

Area of rhombus is given by A = 1/2*d₁*d₂,

But we know, A = 24

Hence, 1/2*d₁*d₂ = 24

1/2*8*d₂ = 24

d₂ = 6 cm.

Hence, length of the other diagonal of rhombus

is 6 cm.