EXERCISE 2.3
3) The population of a city increases each year by 4% of what it had been at the beginning
of each year. If its present population is 6760000, find :
(1) its population 2 years hence (ii) its population 2 years ago.
Answers
Answered by
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Current Population=6760000 , R=4%
After 1 year
Population=6760000+ 100/4 ×6760000=7030400
After 2 years
Population=7030400+ 100/4×7030400=7311616
Since the population of the city is not 7058522 after 2 years.
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Hope it helps you .
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