Math, asked by chetan3477, 11 months ago

EXERCISE 2.3
Determine whether the sum to infinity of the
following G.P.s exist, if exists find them
i) 1 1 1 1
2'4'8' 16'​

Answers

Answered by harendrachoubay
6

The sum to infinity is "1".

Step-by-step explanation:

The given sequence are

\dfrac{1}{2} , \dfrac{1}{4}, \dfrac{1}{8}, \dfrac{1}{16}, ......

Here, first term (a) = \dfrac{1}{2}, common ratio(r) = \dfrac{1}{2}

The given sequence are in GP.

The sum to infinity = \dfrac{a}{1 - r}

= \dfrac{\frac{1}{2} }{1 - \frac{1}{2} }

= 1

Hence, the sum to infinity is 1.

You can also see:

https://www.quora.com/How-does-1-2-1-4-1-8-1-16-till-infinity-have-a-sum-2

Answered by alfiyap805
3

Answer:

Step-by-step explanation:

The given sequence is 1/2,1/4,1/8,1/16.......

We know a=1/2 and r=1/2

Therefore 1/2 exist in G.P

Sum of infinity =a/1-r .........(formula)

Sum of infinity =1/2/1-1/2

Therefore ,Sum Of Infinity =1.

Hope it's may be helpful.

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