Question

EXERCISE 2.3
Find the remainder when x + 3x² + 3x + 1 is divided by
(1) X+1
1
(i) -
2
(ii) x
(iv) x +​

Answer 1

x+1)3x^2+4x+1(3x+1

3x^2+3x

--------------------

1x+1

1x+1

--------------------

0

Answer 2

AnsweR :-

$x + {3x}^{2} + 3x + 1$

$x + 1 = 0$

$x = 0 - 1$

$x = - 1$

By placing -1 inplace of x then -

$p( - 1) = ( - 1) + {3( - 1)}^{2} + 3( - 1) + 1$

$p( - 1) = - 1 + 3 - 3 + 1$

$p( - 1) = 0$

______________________________________

Procedure :-

$\implies$ First we need to find the zero of x+1 the answer came as -1 because when we transposed 1 to the other side it became -1 and when we supracted it with 0 it became -1.

$\implies$ Then we kept -1 inplace of x and then equated it. I put a +3 because when we will multiply -3 by itself 2 times it will become +3.

$\implies$ Then the -3 will get cancelled with +3 and -1 with +1. Then there is nothing left so the answer became 0.

______________________________________