Question

EXERCISE 2.8
1. Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Please answer the above questions with correct explanation

Those who will answer first but the should be correct then I will mark him/her as brainlist.

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In this question some one has answered but there was no explanation

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Answer 1

Answer:

87 is the correct answer

Answer 2

we have to find the largest number which divide 615 and 963 leaving remainder 6 in each case.

so let us subtract 6 from 615 and 963

615-6=609

963−6=957

now lets find the HCF

⇒ prime factorisation of 609=29×3×3

prime factorisation of 957=29×3×11

now lets take out the common factors from both the cases

⇒ 29 and 3

x=29×3=87

∴ 87 is the number which will divide 615 and 963 leaving remainder 6 in each case.