Question

Exercise 20
Solve the following questions using BODMAS
(200 - 26)+ 100 x 4 - 50 = 5
20 + (10 + 6 x 4) = 2 - (20 - 10
70 - 100 = 5 + 10 x 6 -40
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Answer 1

Answer:

Sn = a + (a + d)+(a + 2d) + ... + (ℓ − 2d)+(ℓ − d) + ℓ. 2 n(a + ℓ) . We have found the sum of an arithmetic progression in terms of its first and last terms, a and ℓ, and the number of terms n.

Answer 2

hope will be helps u

thnx 4 asking ✌️