Question

Exercise 21
1. The HCF of two numbers is 128 and their LCM is 7168. If one of the numbers is 896, find the other​

Answer 1

Let the other number be x

so, HCF×LCM = 896x

=> 128×7168=896x

=>x=1024

Answer 2

Answer:

1024

Step-by-step explanation:

HCF = 128

LCM = 7168

First No. = 896

Let the other no. be x.

We know that, LCM x HCF = Product of no.(s)

⇒ 128 x 7168 = 896x

⇒ x = $\frac{128 x 7168}{896}$ = $\frac{7168}{7}$ = 1024

Hope this helps.....