Question

EXERCISE 21.2
Find the area of a right-angled triangle with hypotenuse 26 cm and a side of length 24 cm.​

Answer 1

Answer:

area is 120$cm^2$ is the answer

Step-by-step explanation:

let a be a perpendicular side

then by pythagoras theorem,

$a^2+24^2=26^2$

         a=$\sqrt{26^2-24^2}$

         a=10 cm

area =1/2×a×24

         =1/2×10×24

          =120 $cm^2$

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