Math, asked by dauleekumari0, 9 months ago

EXERCISE 22 (A)
1. The sum of the digits of a two-digit number is 9. The number is 6 times the units di
2. The sum of the digits of a two-digit number is 7. If the digits are reversed, the new
3 equals 4 times the original number. Find the original number.
3. The sum of a number of two digits and of the number formed by reversing the
difference of the digits is 6. Find the number.
4. A certain number between 10 and 100 is 8 times the sum of its digits, and if 45 be
digits will be reversed. Find the number.
5. A number consists of three digits, the right hand being zero. If the left hand and
interchanged the number is diminished by 180. If the left-hand digit be halved
right-hand digits be interchanged the number is diminished by 454. Find the num
[Hint. Let the original number be 100a+10b+0, i.e., 100a+10b, then, by the fi
(100a+10b)-(100b + 10a) = 180 = a - b = 2
+0+ b = 50a + b
By the second condition, new number = 100
50a +96= 454).
and so (100a+105)-(50a + b) = 454 =
Numbers Expressed in the Generalised Form​

Answers

Answered by hemlatanain1941
1

Answer:

1. X=6

Step-by-step explanation:

1.LET THE NUMBER BE X AND THE SECOND NUMBER 9_X

6(X)=10(9_X)+X

6X=90_10X+X

6X=90_9X

15X=90

X=6

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