Question

EXERCISE 3.1
1. Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then.Also three years from now I shall be three times old as you will be." (Isn't this interesting?) Represent this situation algebraically and graphically.​

Answer 1

Step-by-step explanation:

present age

Let Aftabs age be x

Let his daughters age be y

seven years ago

Aftabs age was x-7

daughters age was y-7

three years hence

abtabs age will be x+3

daughters age will be y+3

x-7 = 7*(y-7)

x-7 = 7y -49

x-7y= -42 ------------(1)

x+3=3*(y+3)

x+3 = 3y+9

x-3y=6 ----------------(2)

x-7y= -42

x-3y=6

-4y = -36

y=-36/-4 = 12

x-3*12=6

x=6+36

=42

therefore aftabs age = 42

daughters age=12

Answer 2

Answer:

Let age of aftab be ' x ' and the age of his daughter be ' y '.

According to your question

x - 7 = 7(y - 7)

x - 7 = 7y - 49

x - 7y = -49+7

x - 7y = -42 ----> 1

Then,

x + 3 = 3(y + 3)

x + 3 = 3y + 9

x - 3y = 9 - 3

x - 3y = 6 ----> 2

solving 1 & 2

x - 7y = -42

x - 3y = 6

- + -

-------------------

-4y = -48

y = 48/4

y = 12

substitute the value of y = 12 in equation 1

x - 7y = -42

x - 7(12) = -42

x - 84 = -42

x = -42+ 84

x = 42

So the age of Aftab is x = 42 years and the age of his daughter is y = 12 years..

Thank you ♡