Question

EXERCISE 3.3
1. Solve the following pair of linear equations by the substitution method.
(i) x+y= 14
(ü) s-t=3
x-y=4
+
3 2
= 6
(iii) 3x - y=3
9x - 3y=9
(iv) 0.2x +0.3y = 1.3
0.4x +0.5y = 2.3
3x 5y = -2
(v) V2x+13 y=0
(vi)
2
3
χ
13
3x - 18y = 0
II
+
3 2 6​

Answer 1

x+y= 14

(ü) s-t=3

x-y=4

+

3 2

= 6

(iii) 3x - y=3

9x - 3y=9

(iv) 0.2x +0.3y = 1.3

0.4x +0.5y = 2.3

3x 5y = -2

(v) V2x+13 y=0

(vi)

2

3

χ

13

3x - 18y = 0

II

+

3 2 6